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Question: 1
Describe law of mass action?
Answer: 1
1-4Law of mass reaction:
According to this law the rate at which a substance reacts is directly.
Proportional to its active mass and the rate of a reaction directly proportional to the product of the active masses of the reacting substances.
Derivation for equilibrium constant:
Consider the following reversible reaction:
A+B____kf_______ C+D
kr
Suppose (A) (B) (C) and (D) are moral concentration of A,B,C and D are respectively.
So, a
Rf * (A) (B)
Rf-Kf (A) (B)
Where Rf is rate of forward reaction while KF is a rate constant for forward reaction:
Similarly,
Rr * (C) (D)
Rr = Kr (C) (D)
where Rr is rate of reverse reaction while Kr is the rate constant for a reverse reaction.
At equilibrium state Rf=Rr
By putting the values of Eq 1 and 2 in Eq 3 we have
Kf (A) (B) = Kr (C) (D)
Kf = (C) (D)
Kr = (A) (B)
Kc = (C) (D)
(A) (B)
Kc is a equilibrium constant
Part 6( b)
Macroscopic Characteristics
Dynamic means reaction is still continuing. A few characteristics are given below.
Closed system:
Dynamic equilibrium is attain able only in close vessel because substances can neither leave nor enter in close system.
Concentration remain the same:
Amount of reactants and products do not change at equilibrium state.
Physical properties will not change:
physical properties like colour density etc remain the same.
Reaction does not stop:
Reaction will not cease in dynamic equilibrium forward and reverse reaction keep on talking place at the same rate but in opposite direction. it can be shown as:
Rates of forward _______ Rates of reaction Reverse reaction
Equilibrium can be established from either side.
An equilibrium state can be disturbed and again achieved under certain conditions of concentration pressure and temperature.